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select c.categories_id, cd.categories_name, c.categories_image, c.parent_id from categories c, categories_description cd where c.parent_id = '50' and c.categories_id = cd.categories_id and cd.language_id = '1' order by sort_order, cd.categories_name
[TEP STOP]
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select count(*) as total from sessions where sesskey = '576db530b1d8fce3b2706fd0621f8100'
[TEP STOP]
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